Base | Representation |
---|---|
bin | 111101000001101000… |
… | …0000011101001110001 |
3 | 110112021011122210011200 |
4 | 1322003100003221301 |
5 | 4121343031342231 |
6 | 140112022401413 |
7 | 12316365326643 |
oct | 1720320035161 |
9 | 415234583150 |
10 | 131051043441 |
11 | 5063a99667a |
12 | 21494890269 |
13 | c486874026 |
14 | 64b2d02893 |
15 | 3620278be6 |
hex | 1e83403a71 |
131051043441 has 144 divisors (see below), whose sum is σ = 212865516864. Its totient is φ = 77579783424.
The previous prime is 131051043439. The next prime is 131051043451. The reversal of 131051043441 is 144340150131.
131051043441 is a `hidden beast` number, since 1 + 310 + 5 + 1 + 0 + 4 + 344 + 1 = 666.
It is not a de Polignac number, because 131051043441 - 21 = 131051043439 is a prime.
It is a super-3 number, since 3×1310510434413 (a number of 34 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (131051043401) by changing a digit.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 426876210 + ... + 426876516.
It is an arithmetic number, because the mean of its divisors is an integer number (1478232756).
Almost surely, 2131051043441 is an apocalyptic number.
It is an amenable number.
131051043441 is a deficient number, since it is larger than the sum of its proper divisors (81814473423).
131051043441 is a wasteful number, since it uses less digits than its factorization.
131051043441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 508 (or 486 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 131051043441 its reverse (144340150131), we get a palindrome (275391193572).
The spelling of 131051043441 in words is "one hundred thirty-one billion, fifty-one million, forty-three thousand, four hundred forty-one".
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