Base | Representation |
---|---|
bin | 111101000001101010… |
… | …1110111100110100101 |
3 | 110112021021112012000220 |
4 | 1322003111313212211 |
5 | 4121343424120244 |
6 | 140112115154553 |
7 | 12316414303443 |
oct | 1720325674645 |
9 | 415237465026 |
10 | 131052566949 |
11 | 50640837277 |
12 | 214952a5a59 |
13 | c486c88605 |
14 | 64b31bbb93 |
15 | 362047a319 |
hex | 1e835779a5 |
131052566949 has 4 divisors (see below), whose sum is σ = 174736755936. Its totient is φ = 87368377964.
The previous prime is 131052566941. The next prime is 131052566969. The reversal of 131052566949 is 949665250131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131052566949 - 23 = 131052566941 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131052566941) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21842094489 + ... + 21842094494.
It is an arithmetic number, because the mean of its divisors is an integer number (43684188984).
Almost surely, 2131052566949 is an apocalyptic number.
It is an amenable number.
131052566949 is a deficient number, since it is larger than the sum of its proper divisors (43684188987).
131052566949 is an equidigital number, since it uses as much as digits as its factorization.
131052566949 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43684188986.
The product of its (nonzero) digits is 1749600, while the sum is 51.
The spelling of 131052566949 in words is "one hundred thirty-one billion, fifty-two million, five hundred sixty-six thousand, nine hundred forty-nine".
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