Base | Representation |
---|---|
bin | 1011111010110100111010… |
… | …1010101011010001100101 |
3 | 1201101211222110020010020101 |
4 | 2332231032222223101211 |
5 | 3204204040321431440 |
6 | 43512250423304101 |
7 | 2521552453526323 |
oct | 276551652532145 |
9 | 51354873203211 |
10 | 13105265030245 |
11 | 41a2a03501a63 |
12 | 1577a7a8ab031 |
13 | 740a8a1cc46b |
14 | 334426416d13 |
15 | 17ad70c2a69a |
hex | beb4eaab465 |
13105265030245 has 4 divisors (see below), whose sum is σ = 15726318036300. Its totient is φ = 10484212024192.
The previous prime is 13105265030183. The next prime is 13105265030261. The reversal of 13105265030245 is 54203056250131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1344871618596 + 11760393411649 = 1159686^2 + 3429343^2 .
It is a cyclic number.
It is not a de Polignac number, because 13105265030245 - 229 = 13104728159333 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1310526503020 + ... + 1310526503029.
It is an arithmetic number, because the mean of its divisors is an integer number (3931579509075).
Almost surely, 213105265030245 is an apocalyptic number.
It is an amenable number.
13105265030245 is a deficient number, since it is larger than the sum of its proper divisors (2621053006055).
13105265030245 is an equidigital number, since it uses as much as digits as its factorization.
13105265030245 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2621053006054.
The product of its (nonzero) digits is 108000, while the sum is 37.
The spelling of 13105265030245 in words is "thirteen trillion, one hundred five billion, two hundred sixty-five million, thirty thousand, two hundred forty-five".
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