Base | Representation |
---|---|
bin | 10011000100100001110… |
… | …010100101101010101111 |
3 | 11122021201020001011211221 |
4 | 103010201302211222233 |
5 | 132432432133404040 |
6 | 2442014451324211 |
7 | 163453126435051 |
oct | 23044162455257 |
9 | 4567636034757 |
10 | 1310531934895 |
11 | 465880125817 |
12 | 191ba65b0667 |
13 | 9677606b591 |
14 | 476042178d1 |
15 | 2415385874a |
hex | 13121ca5aaf |
1310531934895 has 4 divisors (see below), whose sum is σ = 1572638321880. Its totient is φ = 1048425547912.
The previous prime is 1310531934893. The next prime is 1310531934947. The reversal of 1310531934895 is 5984391350131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1310531934895 - 21 = 1310531934893 is a prime.
It is a super-2 number, since 2×13105319348952 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1310531934893) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131053193485 + ... + 131053193494.
It is an arithmetic number, because the mean of its divisors is an integer number (393159580470).
Almost surely, 21310531934895 is an apocalyptic number.
1310531934895 is a deficient number, since it is larger than the sum of its proper divisors (262106386985).
1310531934895 is an equidigital number, since it uses as much as digits as its factorization.
1310531934895 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 262106386984.
The product of its (nonzero) digits is 1749600, while the sum is 52.
The spelling of 1310531934895 in words is "one trillion, three hundred ten billion, five hundred thirty-one million, nine hundred thirty-four thousand, eight hundred ninety-five".
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