Base | Representation |
---|---|
bin | 1011111010110101001010… |
… | …0011010110110001001111 |
3 | 1201101212010222220002220212 |
4 | 2332231102203112301033 |
5 | 3204204204014020421 |
6 | 43512301112433035 |
7 | 2521554204610253 |
oct | 276552243266117 |
9 | 51355128802825 |
10 | 13105330220111 |
11 | 41a2a37288088 |
12 | 1577a986a877b |
13 | 740a9a87574c |
14 | 334430d46263 |
15 | 17ad76805e5b |
hex | beb528d6c4f |
13105330220111 has 4 divisors (see below), whose sum is σ = 13109628462000. Its totient is φ = 13101031978224.
The previous prime is 13105330220051. The next prime is 13105330220179. The reversal of 13105330220111 is 11102203350131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13105330220111 - 222 = 13105326025807 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13105330226111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2149116371 + ... + 2149122468.
It is an arithmetic number, because the mean of its divisors is an integer number (3277407115500).
Almost surely, 213105330220111 is an apocalyptic number.
13105330220111 is a deficient number, since it is larger than the sum of its proper divisors (4298241889).
13105330220111 is an equidigital number, since it uses as much as digits as its factorization.
13105330220111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4298241888.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 13105330220111 its reverse (11102203350131), we get a palindrome (24207533570242).
The spelling of 13105330220111 in words is "thirteen trillion, one hundred five billion, three hundred thirty million, two hundred twenty thousand, one hundred eleven".
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