Base | Representation |
---|---|
bin | 1011111010110101011100… |
… | …0010101001111110100011 |
3 | 1201101212100020121110022102 |
4 | 2332231113002221332203 |
5 | 3204204332304042430 |
6 | 43512312403001015 |
7 | 2521556111015516 |
oct | 276552702517643 |
9 | 51355306543272 |
10 | 13105405534115 |
11 | 41a2a75848664 |
12 | 1577ab996916b |
13 | 740ab0354c4b |
14 | 33443ad4cd7d |
15 | 17ad7d231345 |
hex | beb570a9fa3 |
13105405534115 has 4 divisors (see below), whose sum is σ = 15726486640944. Its totient is φ = 10484324427288.
The previous prime is 13105405534103. The next prime is 13105405534157. The reversal of 13105405534115 is 51143550450131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13105405534115 - 26 = 13105405534051 is a prime.
It is a super-2 number, since 2×131054055341152 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1310540553407 + ... + 1310540553416.
It is an arithmetic number, because the mean of its divisors is an integer number (3931621660236).
Almost surely, 213105405534115 is an apocalyptic number.
13105405534115 is a deficient number, since it is larger than the sum of its proper divisors (2621081106829).
13105405534115 is an equidigital number, since it uses as much as digits as its factorization.
13105405534115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2621081106828.
The product of its (nonzero) digits is 90000, while the sum is 38.
Adding to 13105405534115 its reverse (51143550450131), we get a palindrome (64248955984246).
The spelling of 13105405534115 in words is "thirteen trillion, one hundred five billion, four hundred five million, five hundred thirty-four thousand, one hundred fifteen".
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