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13105435021501 = 17597450503139
BaseRepresentation
bin1011111010110101100011…
…0011001001000010111101
31201101212102022002120101211
42332231120303021002331
53204204412331142001
643512315335004421
72521556616450544
oct276553063110275
951355368076354
1013105435021501
1141a2a904589a9
121577b07809711
13740ab64aa7c4
14334440c2715b
1517ad80b08351
hexbeb58cc90bd

13105435021501 has 4 divisors (see below), whose sum is σ = 13112885526400. Its totient is φ = 13097984516604.

The previous prime is 13105435021397. The next prime is 13105435021513. The reversal of 13105435021501 is 10512053450131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13105435021501 - 213 = 13105435013309 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13105435021561) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3725249811 + ... + 3725253328.

It is an arithmetic number, because the mean of its divisors is an integer number (3278221381600).

Almost surely, 213105435021501 is an apocalyptic number.

It is an amenable number.

13105435021501 is a deficient number, since it is larger than the sum of its proper divisors (7450504899).

13105435021501 is an equidigital number, since it uses as much as digits as its factorization.

13105435021501 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7450504898.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 13105435021501 its reverse (10512053450131), we get a palindrome (23617488471632).

The spelling of 13105435021501 in words is "thirteen trillion, one hundred five billion, four hundred thirty-five million, twenty-one thousand, five hundred one".

Divisors: 1 1759 7450503139 13105435021501