Base | Representation |
---|---|
bin | 1011111010110101110110… |
… | …0001111101101000000010 |
3 | 1201101212121211110122012111 |
4 | 2332231131201331220002 |
5 | 3204210043141414404 |
6 | 43512331252245534 |
7 | 2521561602263461 |
oct | 276553541755002 |
9 | 51355554418174 |
10 | 13105514404354 |
11 | 41a3021248469 |
12 | 1577b2a3108aa |
13 | 740ac9a82cc8 |
14 | 33444b5ac9d8 |
15 | 17ad87a89104 |
hex | beb5d87da02 |
13105514404354 has 4 divisors (see below), whose sum is σ = 19658271606534. Its totient is φ = 6552757202176.
The previous prime is 13105514404319. The next prime is 13105514404373. The reversal of 13105514404354 is 45340441550131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 7018552055025 + 6086962349329 = 2649255^2 + 2467177^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3276378601087 + ... + 3276378601090.
Almost surely, 213105514404354 is an apocalyptic number.
13105514404354 is a deficient number, since it is larger than the sum of its proper divisors (6552757202180).
13105514404354 is an equidigital number, since it uses as much as digits as its factorization.
13105514404354 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6552757202179.
The product of its (nonzero) digits is 288000, while the sum is 40.
Adding to 13105514404354 its reverse (45340441550131), we get a palindrome (58445955954485).
The spelling of 13105514404354 in words is "thirteen trillion, one hundred five billion, five hundred fourteen million, four hundred four thousand, three hundred fifty-four".
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