13105645243 has 4 divisors (see below), whose sum is σ = 13110773200. Its totient is φ = 13100517288.

The previous prime is 13105645177. The next prime is 13105645247. The reversal of 13105645243 is 34254650131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13105645243 - 2¹⁷ = 13105514171 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13105645199 and 13105645208.

It is not an unprimeable number, because it can be changed into a prime (13105645247) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2560143 + ... + 2565256.

It is an arithmetic number, because the mean of its divisors is an integer number (3277693300).

Almost surely, 2^13105645243 is an apocalyptic number.

13105645243 is a deficient number, since it is larger than the sum of its proper divisors (5127957).

13105645243 is an equidigital number, since it uses as much as digits as its factorization.

13105645243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5127956.

The product of its (nonzero) digits is 43200, while the sum is 34.

The spelling of 13105645243 in words is "thirteen billion, one hundred five million, six hundred forty-five thousand, two hundred forty-three".