Base | Representation |
---|---|
bin | 1011111010111010000011… |
… | …1000110000000000001101 |
3 | 1201101222112120211222020121 |
4 | 2332232200320300000031 |
5 | 3204214401434420331 |
6 | 43513035341144541 |
7 | 2521631603442220 |
oct | 276564070600015 |
9 | 51358476758217 |
10 | 13106644451341 |
11 | 41a35511154a1 |
12 | 15781a485b151 |
13 | 740c49c2416c |
14 | 3345176cd5b7 |
15 | 17ae01da7c11 |
hex | beba0e3000d |
13106644451341 has 16 divisors (see below), whose sum is σ = 15865053431040. Its totient is φ = 10570152625920.
The previous prime is 13106644451339. The next prime is 13106644451353. The reversal of 13106644451341 is 14315444660131.
It is a cyclic number.
It is not a de Polignac number, because 13106644451341 - 21 = 13106644451339 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13106644451941) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16670545 + ... + 17439046.
It is an arithmetic number, because the mean of its divisors is an integer number (991565839440).
Almost surely, 213106644451341 is an apocalyptic number.
It is an amenable number.
13106644451341 is a deficient number, since it is larger than the sum of its proper divisors (2758408979699).
13106644451341 is a wasteful number, since it uses less digits than its factorization.
13106644451341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34112844.
The product of its (nonzero) digits is 414720, while the sum is 43.
The spelling of 13106644451341 in words is "thirteen trillion, one hundred six billion, six hundred forty-four million, four hundred fifty-one thousand, three hundred forty-one".
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