1311001312231 has 4 divisors (see below), whose sum is σ = 1411847567032. Its totient is φ = 1210155057432.

The previous prime is 1311001312223. The next prime is 1311001312259. The reversal of 1311001312231 is 1322131001131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311001312231 - 2³ = 1311001312223 is a prime.

It is a super-2 number, since 2×1311001312231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311001312199 and 1311001312208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311001312031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50423127381 + ... + 50423127406.

It is an arithmetic number, because the mean of its divisors is an integer number (352961891758).

Almost surely, 2^{1311001312231} is an apocalyptic number.

1311001312231 is a deficient number, since it is larger than the sum of its proper divisors (100846254801).

1311001312231 is a wasteful number, since it uses less digits than its factorization.

1311001312231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100846254800.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1311001312231 its reverse (1322131001131), we get a palindrome (2633132313362).

The spelling of 1311001312231 in words is "one trillion, three hundred eleven billion, one million, three hundred twelve thousand, two hundred thirty-one".