131100132015 has 16 divisors (see below), whose sum is σ = 233066901600. Its totient is φ = 69920070336.

The previous prime is 131100131989. The next prime is 131100132019. The reversal of 131100132015 is 510231001131.

It is not a de Polignac number, because 131100132015 - 2¹⁶ = 131100066479 is a prime.

It is a super-2 number, since 2×131100132015² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131100132019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 485555910 + ... + 485556179.

It is an arithmetic number, because the mean of its divisors is an integer number (14566681350).

Almost surely, 2^131100132015 is an apocalyptic number.

131100132015 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

131100132015 is a deficient number, since it is larger than the sum of its proper divisors (101966769585).

131100132015 is an equidigital number, since it uses as much as digits as its factorization.

131100132015 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 971112103 (or 971112097 counting only the distinct ones).

The product of its (nonzero) digits is 90, while the sum is 18.

Adding to 131100132015 its reverse (510231001131), we get a palindrome (641331133146).

The spelling of 131100132015 in words is "one hundred thirty-one billion, one hundred million, one hundred thirty-two thousand, fifteen".