1311001320331 has 4 divisors (see below), whose sum is σ = 1311390229464. Its totient is φ = 1310612411200.

The previous prime is 1311001320323. The next prime is 1311001320337. The reversal of 1311001320331 is 1330231001131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311001320331 - 2³ = 1311001320323 is a prime.

It is a super-2 number, since 2×1311001320331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311001320299 and 1311001320308.

It is not an unprimeable number, because it can be changed into a prime (1311001320337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 194449510 + ... + 194456251.

It is an arithmetic number, because the mean of its divisors is an integer number (327847557366).

Almost surely, 2^{1311001320331} is an apocalyptic number.

1311001320331 is a deficient number, since it is larger than the sum of its proper divisors (388909133).

1311001320331 is an equidigital number, since it uses as much as digits as its factorization.

1311001320331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 388909132.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1311001320331 its reverse (1330231001131), we get a palindrome (2641232321462).

The spelling of 1311001320331 in words is "one trillion, three hundred eleven billion, one million, three hundred twenty thousand, three hundred thirty-one".