Base | Representation |
---|---|
bin | 10011000100111101110… |
… | …001001001101110010001 |
3 | 11122022220221021102121221 |
4 | 103010331301021232101 |
5 | 132434412314222322 |
6 | 2442133220045041 |
7 | 163500556233532 |
oct | 23047561115621 |
9 | 4568827242557 |
10 | 1311001320337 |
11 | 465aa1081a75 |
12 | 1920b7833781 |
13 | 9681c394a47 |
14 | 4764a6c0689 |
15 | 2417eb759c7 |
hex | 1313dc49b91 |
1311001320337 has 2 divisors, whose sum is σ = 1311001320338. Its totient is φ = 1311001320336.
The previous prime is 1311001320323. The next prime is 1311001320371. The reversal of 1311001320337 is 7330231001131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1307983356241 + 3017964096 = 1143671^2 + 54936^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311001320337 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311001320137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655500660168 + 655500660169.
It is an arithmetic number, because the mean of its divisors is an integer number (655500660169).
Almost surely, 21311001320337 is an apocalyptic number.
It is an amenable number.
1311001320337 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311001320337 is an equidigital number, since it uses as much as digits as its factorization.
1311001320337 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 25.
Adding to 1311001320337 its reverse (7330231001131), we get a palindrome (8641232321468).
The spelling of 1311001320337 in words is "one trillion, three hundred eleven billion, one million, three hundred twenty thousand, three hundred thirty-seven".
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