13110021000001 has 4 divisors (see below), whose sum is σ = 13111238169904. Its totient is φ = 13108803830100.

The previous prime is 13110020999951. The next prime is 13110021000007. The reversal of 13110021000001 is 10000012001131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13110021000001 - 2²⁹ = 13109484129089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13110021000007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 608568795 + ... + 608590336.

It is an arithmetic number, because the mean of its divisors is an integer number (3277809542476).

Almost surely, 2^{13110021000001} is an apocalyptic number.

It is an amenable number.

13110021000001 is a deficient number, since it is larger than the sum of its proper divisors (1217169903).

13110021000001 is a wasteful number, since it uses less digits than its factorization.

13110021000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1217169902.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 13110021000001 its reverse (10000012001131), we get a palindrome (23110033001132).

The spelling of 13110021000001 in words is "thirteen trillion, one hundred ten billion, twenty-one million, one", and thus it is an aban number.