Base | Representation |
---|---|
bin | 10011000100111101110… |
… | …111100011110110011111 |
3 | 11122022221001102202222221 |
4 | 103010331313203312133 |
5 | 132434413232001343 |
6 | 2442133320050211 |
7 | 163500606431260 |
oct | 23047567436637 |
9 | 4568831382887 |
10 | 1311003000223 |
11 | 465aa201a104 |
12 | 1920b8303967 |
13 | 9681c832567 |
14 | 4764a9da967 |
15 | 2417eda85ed |
hex | 1313dde3d9f |
1311003000223 has 8 divisors (see below), whose sum is σ = 1498349734560. Its totient is φ = 1123671413760.
The previous prime is 1311003000193. The next prime is 1311003000227. The reversal of 1311003000223 is 3220003001131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1311003000223 - 29 = 1311002999711 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1311003000197 and 1311003000206.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311003000227) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3600898 + ... + 3948223.
It is an arithmetic number, because the mean of its divisors is an integer number (187293716820).
Almost surely, 21311003000223 is an apocalyptic number.
1311003000223 is a deficient number, since it is larger than the sum of its proper divisors (187346734337).
1311003000223 is an equidigital number, since it uses as much as digits as its factorization.
1311003000223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7573937.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 1311003000223 its reverse (3220003001131), we get a palindrome (4531006001354).
The spelling of 1311003000223 in words is "one trillion, three hundred eleven billion, three million, two hundred twenty-three", and thus it is an aban number.
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