13110044402041 has 8 divisors (see below), whose sum is σ = 13890521048904. Its totient is φ = 12330600817920.

The previous prime is 13110044402027. The next prime is 13110044402047. The reversal of 13110044402041 is 14020444001131.

It can be written as a sum of positive squares in 4 ways, for example, as 6731969916816 + 6378074485225 = 2594604^2 + 2525485^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13110044402041 is a prime.

It is a super-2 number, since 2×13110044402041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13110044401997 and 13110044402015.

It is not an unprimeable number, because it can be changed into a prime (13110044402047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 258239550 + ... + 258290311.

It is an arithmetic number, because the mean of its divisors is an integer number (1736315131113).

Almost surely, 2^{13110044402041} is an apocalyptic number.

It is an amenable number.

13110044402041 is a deficient number, since it is larger than the sum of its proper divisors (780476646863).

13110044402041 is a wasteful number, since it uses less digits than its factorization.

13110044402041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 516531371.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 13110044402041 its reverse (14020444001131), we get a palindrome (27130488403172).

The spelling of 13110044402041 in words is "thirteen trillion, one hundred ten billion, forty-four million, four hundred two thousand, forty-one".