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13110100042013 = 131019984843901
BaseRepresentation
bin1011111011000110111011…
…0110110010000100011101
31201102022110102011011111022
42332301232312302010131
53204243441102321023
643514410302333525
72522113333460462
oct276615666620435
951368412134438
1013110100042013
1141a4a6476a957
1215789a9b8a2a5
1374137ab11c80
1433476460b669
1517b0554417c8
hexbec6edb211d

13110100042013 has 8 divisors (see below), whose sum is σ = 14258357092056. Its totient is φ = 11981812680000.

The previous prime is 13110100041991. The next prime is 13110100042079. The reversal of 13110100042013 is 31024000101131.

It can be written as a sum of positive squares in 4 ways, for example, as 3929521219204 + 9180578822809 = 1982302^2 + 3029947^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13110100042013 - 26 = 13110100041949 is a prime.

It is a super-2 number, since 2×131101000420132 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13110100041982 and 13110100042000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110100042093) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4992420638 + ... + 4992423263.

It is an arithmetic number, because the mean of its divisors is an integer number (1782294636507).

Almost surely, 213110100042013 is an apocalyptic number.

13110100042013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13110100042013 is a deficient number, since it is larger than the sum of its proper divisors (1148257050043).

13110100042013 is a wasteful number, since it uses less digits than its factorization.

13110100042013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9984844015.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13110100042013 its reverse (31024000101131), we get a palindrome (44134100143144).

The spelling of 13110100042013 in words is "thirteen trillion, one hundred ten billion, one hundred million, forty-two thousand, thirteen".

Divisors: 1 13 101 1313 9984843901 129802970713 1008469234001 13110100042013