Search a number
-
+
13110100401440 = 255723677596007
BaseRepresentation
bin1011111011000110111011…
…1000001001110100100000
31201102022110102211102112102
42332301232320021310200
53204243441200321230
643514410314145532
72522113336515410
oct276615670116440
951368412742472
1013110100401440
1141a4a649959a9
1215789aa1222a8
1374137ac09753
143347646a2640
1517b0554b3045
hexbec6ee09d20

13110100401440 has 192 divisors, whose sum is σ = 37487575609344. Its totient is φ = 4235289873408.

The previous prime is 13110100401427. The next prime is 13110100401499. The reversal of 13110100401440 is 4410400101131.

13110100401440 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2072084 + ... + 5523923.

It is an arithmetic number, because the mean of its divisors is an integer number (195247789632).

Almost surely, 213110100401440 is an apocalyptic number.

13110100401440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13110100401440 is an abundant number, since it is smaller than the sum of its proper divisors (24377475207904).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13110100401440 is a wasteful number, since it uses less digits than its factorization.

13110100401440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7596119 (or 7596111 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 13110100401440 its reverse (4410400101131), we get a palindrome (17520500502571).

The spelling of 13110100401440 in words is "thirteen trillion, one hundred ten billion, one hundred million, four hundred one thousand, four hundred forty".