Base | Representation |
---|---|
bin | 1011111011000110111110… |
… | …0001011100000110110001 |
3 | 1201102022111012012021121220 |
4 | 2332301233201130012301 |
5 | 3204244001433133431 |
6 | 43514411342135253 |
7 | 2522113530512643 |
oct | 276615741340661 |
9 | 51368435167556 |
10 | 13110111224241 |
11 | 41a4a70008269 |
12 | 15789b1881529 |
13 | 741380228985 |
14 | 334765cbc893 |
15 | 17b0563eeb96 |
hex | bec6f85c1b1 |
13110111224241 has 8 divisors (see below), whose sum is σ = 17480173412160. Its totient is φ = 8740061592912.
The previous prime is 13110111224209. The next prime is 13110111224291. The reversal of 13110111224241 is 14242211101131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13110111224241 - 25 = 13110111224209 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13110111224201) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 348565 + ... + 5132418.
It is an arithmetic number, because the mean of its divisors is an integer number (2185021676520).
Almost surely, 213110111224241 is an apocalyptic number.
It is an amenable number.
13110111224241 is a deficient number, since it is larger than the sum of its proper divisors (4370062187919).
13110111224241 is an equidigital number, since it uses as much as digits as its factorization.
13110111224241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6278295.
The product of its (nonzero) digits is 384, while the sum is 24.
Adding to 13110111224241 its reverse (14242211101131), we get a palindrome (27352322325372).
The spelling of 13110111224241 in words is "thirteen trillion, one hundred ten billion, one hundred eleven million, two hundred twenty-four thousand, two hundred forty-one".
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