Base | Representation |
---|---|
bin | 11101110011110001100010… |
… | …010000011100110011010111 |
3 | 122012012011012010221211120202 |
4 | 131303301202100130303113 |
5 | 114140430304414110201 |
6 | 1142455023531251115 |
7 | 36420515462150621 |
oct | 3563614220346327 |
9 | 565164163854522 |
10 | 131101230222551 |
11 | 388557a0727676 |
12 | 128543688a9a9b |
13 | 581ca401a6ca4 |
14 | 2453494bc1c11 |
15 | 102539d054c6b |
hex | 773c6241ccd7 |
131101230222551 has 12 divisors (see below), whose sum is σ = 137081737420320. Its totient is φ = 125371324293600.
The previous prime is 131101230222509. The next prime is 131101230222563. The reversal of 131101230222551 is 155222032101131.
It is a de Polignac number, because none of the positive numbers 2k-131101230222551 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131101230222581) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 27274031 + ... + 31718688.
It is an arithmetic number, because the mean of its divisors is an integer number (11423478118360).
Almost surely, 2131101230222551 is an apocalyptic number.
131101230222551 is a deficient number, since it is larger than the sum of its proper divisors (5980507197769).
131101230222551 is an equidigital number, since it uses as much as digits as its factorization.
131101230222551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58996966 (or 58996943 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 29.
Adding to 131101230222551 its reverse (155222032101131), we get a palindrome (286323262323682).
The spelling of 131101230222551 in words is "one hundred thirty-one trillion, one hundred one billion, two hundred thirty million, two hundred twenty-two thousand, five hundred fifty-one".
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