13110124124041 has 16 divisors (see below), whose sum is σ = 15214921113600. Its totient is φ = 11064100112208.

The previous prime is 13110124124029. The next prime is 13110124124059. The reversal of 13110124124041 is 14042142101131.

13110124124041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 13110124124041 - 2¹⁷ = 13110123992969 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13110124123997 and 13110124124015.

It is not an unprimeable number, because it can be changed into a prime (13110124124011) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 32819965 + ... + 33217018.

It is an arithmetic number, because the mean of its divisors is an integer number (950932569600).

Almost surely, 2^{13110124124041} is an apocalyptic number.

It is an amenable number.

13110124124041 is a deficient number, since it is larger than the sum of its proper divisors (2104796989559).

13110124124041 is an equidigital number, since it uses as much as digits as its factorization.

13110124124041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66037428.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 13110124124041 its reverse (14042142101131), we get a palindrome (27152266225172).

The spelling of 13110124124041 in words is "thirteen trillion, one hundred ten billion, one hundred twenty-four million, one hundred twenty-four thousand, forty-one".