131101334401441 has 4 divisors (see below), whose sum is σ = 131101944818500. Its totient is φ = 131100723984384.

The previous prime is 131101334401417. The next prime is 131101334401451. The reversal of 131101334401441 is 144104433101131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 80559600250000 + 50541734151441 = 8975500^2 + 7109271^2 .

It is a cyclic number.

It is not a de Polignac number, because 131101334401441 - 2²⁵ = 131101300847009 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131101334401451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 304886256 + ... + 305315953.

It is an arithmetic number, because the mean of its divisors is an integer number (32775486204625).

Almost surely, 2^{131101334401441} is an apocalyptic number.

It is an amenable number.

131101334401441 is a deficient number, since it is larger than the sum of its proper divisors (610417059).

131101334401441 is an equidigital number, since it uses as much as digits as its factorization.

131101334401441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 610417058.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 131101334401441 its reverse (144104433101131), we get a palindrome (275205767502572).

The spelling of 131101334401441 in words is "one hundred thirty-one trillion, one hundred one billion, three hundred thirty-four million, four hundred one thousand, four hundred forty-one".