Base | Representation |
---|---|
bin | 11101110011110001101000… |
… | …110111000101110100110001 |
3 | 122012012011110212102200201120 |
4 | 131303301220313011310301 |
5 | 114140431021244442340 |
6 | 1142455042530052453 |
7 | 36420521305653651 |
oct | 3563615067056461 |
9 | 565164425380646 |
10 | 131101341015345 |
11 | 3885584821a968 |
12 | 12854399a1a129 |
13 | 581ca5a12915c |
14 | 24534a57c2361 |
15 | 10253a7b3c4d0 |
hex | 773c68dc5d31 |
131101341015345 has 128 divisors (see below), whose sum is σ = 231696267264000. Its totient is φ = 63005107765248.
The previous prime is 131101341015331. The next prime is 131101341015373. The reversal of 131101341015345 is 543510143101131.
It is not a de Polignac number, because 131101341015345 - 28 = 131101341015089 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 3095715231 + ... + 3095757579.
It is an arithmetic number, because the mean of its divisors is an integer number (1810127088000).
Almost surely, 2131101341015345 is an apocalyptic number.
131101341015345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
131101341015345 is a deficient number, since it is larger than the sum of its proper divisors (100594926248655).
131101341015345 is a wasteful number, since it uses less digits than its factorization.
131101341015345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45039.
The product of its (nonzero) digits is 10800, while the sum is 33.
Adding to 131101341015345 its reverse (543510143101131), we get a palindrome (674611484116476).
The spelling of 131101341015345 in words is "one hundred thirty-one trillion, one hundred one billion, three hundred forty-one million, fifteen thousand, three hundred forty-five".
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