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13110144441 = 34370048147
BaseRepresentation
bin11000011010110110…
…01110110110111001
31020211200001100020020
430031123032312321
5203322144110231
610004523521053
7642611250312
oct141533166671
936750040206
1013110144441
115618375619
12265a689189
13130c157a24
148c523b609
1551ae5c396
hex30d6cedb9

13110144441 has 4 divisors (see below), whose sum is σ = 17480192592. Its totient is φ = 8740096292.

The previous prime is 13110144413. The next prime is 13110144449. The reversal of 13110144441 is 14444101131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13110144441 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13110144449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185024071 + ... + 2185024076.

It is an arithmetic number, because the mean of its divisors is an integer number (4370048148).

Almost surely, 213110144441 is an apocalyptic number.

It is an amenable number.

13110144441 is a deficient number, since it is larger than the sum of its proper divisors (4370048151).

13110144441 is an equidigital number, since it uses as much as digits as its factorization.

13110144441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4370048150.

The product of its (nonzero) digits is 768, while the sum is 24.

Adding to 13110144441 its reverse (14444101131), we get a palindrome (27554245572).

The spelling of 13110144441 in words is "thirteen billion, one hundred ten million, one hundred forty-four thousand, four hundred forty-one".

Divisors: 1 3 4370048147 13110144441