Base | Representation |
---|---|
bin | 11000011010110110… |
… | …01111110110010111 |
3 | 1020211200001112210200 |
4 | 30031123033312113 |
5 | 203322144223003 |
6 | 10004523551543 |
7 | 642611265204 |
oct | 141533176627 |
9 | 36750045720 |
10 | 13110148503 |
11 | 5618378681 |
12 | 265a68b5b3 |
13 | 130c15982a |
14 | 8c523ccab |
15 | 51ae5d6a3 |
hex | 30d6cfd97 |
13110148503 has 6 divisors (see below), whose sum is σ = 18936881184. Its totient is φ = 8740098996.
The previous prime is 13110148489. The next prime is 13110148531. The reversal of 13110148503 is 30584101131.
13110148503 is a `hidden beast` number, since 1 + 3 + 1 + 10 + 148 + 503 = 666.
It is not a de Polignac number, because 13110148503 - 212 = 13110144407 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13110148003) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 728341575 + ... + 728341592.
It is an arithmetic number, because the mean of its divisors is an integer number (3156146864).
Almost surely, 213110148503 is an apocalyptic number.
13110148503 is a deficient number, since it is larger than the sum of its proper divisors (5826732681).
13110148503 is a wasteful number, since it uses less digits than its factorization.
13110148503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1456683173 (or 1456683170 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 27.
Adding to 13110148503 its reverse (30584101131), we get a palindrome (43694249634).
The spelling of 13110148503 in words is "thirteen billion, one hundred ten million, one hundred forty-eight thousand, five hundred three".
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