1311021300031 has 4 divisors (see below), whose sum is σ = 1311067202200. Its totient is φ = 1310975397864.

The previous prime is 1311021300013. The next prime is 1311021300079. The reversal of 1311021300031 is 1300031201131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311021300031 - 2⁹ = 1311021299519 is a prime.

It is a super-2 number, since 2×1311021300031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311021299978 and 1311021300014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311021300431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22908216 + ... + 22965373.

It is an arithmetic number, because the mean of its divisors is an integer number (327766800550).

Almost surely, 2^{1311021300031} is an apocalyptic number.

1311021300031 is a deficient number, since it is larger than the sum of its proper divisors (45902169).

1311021300031 is an equidigital number, since it uses as much as digits as its factorization.

1311021300031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45902168.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1311021300031 its reverse (1300031201131), we get a palindrome (2611052501162).

The spelling of 1311021300031 in words is "one trillion, three hundred eleven billion, twenty-one million, three hundred thousand, thirty-one".