13110214301 has 4 divisors (see below), whose sum is σ = 13800225600. Its totient is φ = 12420203004.

The previous prime is 13110214297. The next prime is 13110214319. The reversal of 13110214301 is 10341201131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13110214301 - 2² = 13110214297 is a prime.

It is a super-3 number, since 3×13110214301³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13110214301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110214391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 345005621 + ... + 345005658.

It is an arithmetic number, because the mean of its divisors is an integer number (3450056400).

Almost surely, 2^13110214301 is an apocalyptic number.

It is an amenable number.

13110214301 is a deficient number, since it is larger than the sum of its proper divisors (690011299).

13110214301 is an equidigital number, since it uses as much as digits as its factorization.

13110214301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 690011298.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13110214301 its reverse (10341201131), we get a palindrome (23451415432).

The spelling of 13110214301 in words is "thirteen billion, one hundred ten million, two hundred fourteen thousand, three hundred one".