Base | Representation |
---|---|
bin | 11101110011110010011101… |
… | …110111110101110000111011 |
3 | 122012012020202211222022210212 |
4 | 131303302131313311300323 |
5 | 114140434331440413110 |
6 | 1142455311100501335 |
7 | 36420552325436153 |
oct | 3563623567656073 |
9 | 565166684868725 |
10 | 131102230404155 |
11 | 3885616426493a |
12 | 128545a784a84b |
13 | 581cb6c478a1a |
14 | 245354b979763 |
15 | 102540ac6ee05 |
hex | 773c9ddf5c3b |
131102230404155 has 8 divisors (see below), whose sum is σ = 157386447345552. Its totient is φ = 104839270416288.
The previous prime is 131102230404137. The next prime is 131102230404203. The reversal of 131102230404155 is 551404032201131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131102230404155 - 212 = 131102230400059 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5314224812 + ... + 5314249481.
It is an arithmetic number, because the mean of its divisors is an integer number (19673305918194).
Almost surely, 2131102230404155 is an apocalyptic number.
131102230404155 is a deficient number, since it is larger than the sum of its proper divisors (26284216941397).
131102230404155 is a wasteful number, since it uses less digits than its factorization.
131102230404155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10628476765.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 131102230404155 its reverse (551404032201131), we get a palindrome (682506262605286).
The spelling of 131102230404155 in words is "one hundred thirty-one trillion, one hundred two billion, two hundred thirty million, four hundred four thousand, one hundred fifty-five".
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