13110302431 has 4 divisors (see below), whose sum is σ = 13156628872. Its totient is φ = 13063975992.

The previous prime is 13110302419. The next prime is 13110302449. The reversal of 13110302431 is 13420301131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13420301131 = 139 ⋅96548929.

It is a cyclic number.

It is not a de Polignac number, because 13110302431 - 2⁵ = 13110302399 is a prime.

It is a super-2 number, since 2×13110302431² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13110302399 and 13110302408.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110302831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23162796 + ... + 23163361.

It is an arithmetic number, because the mean of its divisors is an integer number (3289157218).

Almost surely, 2^13110302431 is an apocalyptic number.

13110302431 is a deficient number, since it is larger than the sum of its proper divisors (46326441).

13110302431 is an equidigital number, since it uses as much as digits as its factorization.

13110302431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46326440.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13110302431 its reverse (13420301131), we get a palindrome (26530603562).

The spelling of 13110302431 in words is "thirteen billion, one hundred ten million, three hundred two thousand, four hundred thirty-one".