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13110311214545 = 52622062242909
BaseRepresentation
bin1011111011000111101101…
…1100010101110111010001
31201102100000010111211202012
42332301323130111313101
53204244404132331140
643514443244432305
72522121506430026
oct276617334256721
951370003454665
1013110311214545
1141a5062993a06
121578a48848695
137413b27ab72c
1433478469b54d
1517b068c56265
hexbec7b715dd1

13110311214545 has 4 divisors (see below), whose sum is σ = 15732373457460. Its totient is φ = 10488248971632.

The previous prime is 13110311214503. The next prime is 13110311214569. The reversal of 13110311214545 is 54541211301131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5887552839184 + 7222758375361 = 2426428^2 + 2687519^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110311214545 - 212 = 13110311210449 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1311031121450 + ... + 1311031121459.

It is an arithmetic number, because the mean of its divisors is an integer number (3933093364365).

Almost surely, 213110311214545 is an apocalyptic number.

It is an amenable number.

13110311214545 is a deficient number, since it is larger than the sum of its proper divisors (2622062242915).

13110311214545 is an equidigital number, since it uses as much as digits as its factorization.

13110311214545 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2622062242914.

The product of its (nonzero) digits is 7200, while the sum is 32.

Adding to 13110311214545 its reverse (54541211301131), we get a palindrome (67651522515676).

The spelling of 13110311214545 in words is "thirteen trillion, one hundred ten billion, three hundred eleven million, two hundred fourteen thousand, five hundred forty-five".

Divisors: 1 5 2622062242909 13110311214545