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131103224442045 = 345323711665289
BaseRepresentation
bin11101110011110011011001…
…000111110010110010111101
3122012012100100010102200110000
4131303303121013302302331
5114140443400424121140
61142455553450304513
736420616055555622
oct3563633107626275
9565170303380400
10131103224442045
1138856624386259
1212854824728139
13581cc9a3a921b
1424536039b4349
151025468174a30
hex773cd91f2cbd

131103224442045 has 20 divisors (see below), whose sum is σ = 235014669000540. Its totient is φ = 69921719702208.

The previous prime is 131103224442023. The next prime is 131103224442053. The reversal of 131103224442045 is 540244422301131.

131103224442045 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 0 + 3 + 2 + 2 + 444 + 204 + 5 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 29167970944644 + 101935253497401 = 5400738^2 + 10096299^2 .

It is not a de Polignac number, because 131103224442045 - 212 = 131103224437949 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 161855832240 + ... + 161855833049.

It is an arithmetic number, because the mean of its divisors is an integer number (11750733450027).

Almost surely, 2131103224442045 is an apocalyptic number.

131103224442045 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

131103224442045 is a deficient number, since it is larger than the sum of its proper divisors (103911444558495).

131103224442045 is an equidigital number, since it uses as much as digits as its factorization.

131103224442045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 323711665306 (or 323711665297 counting only the distinct ones).

The product of its (nonzero) digits is 92160, while the sum is 36.

Adding to 131103224442045 its reverse (540244422301131), we get a palindrome (671347646743176).

The spelling of 131103224442045 in words is "one hundred thirty-one trillion, one hundred three billion, two hundred twenty-four million, four hundred forty-two thousand, forty-five".

Divisors: 1 3 5 9 15 27 45 81 135 405 323711665289 971134995867 1618558326445 2913404987601 4855674979335 8740214962803 14567024938005 26220644888409 43701074814015 131103224442045