Base | Representation |
---|---|
bin | 11101110011110011100000… |
… | …001000010010011011110001 |
3 | 122012012100122022122212022011 |
4 | 131303303200020102123301 |
5 | 114140444121023342040 |
6 | 1142500013250242521 |
7 | 36420622014106606 |
oct | 3563634010223361 |
9 | 565170568585264 |
10 | 131103342012145 |
11 | 38856684788428 |
12 | 12854857b86441 |
13 | 581ccb8862129 |
14 | 245361545a6ad |
15 | 102547364a3ea |
hex | 773ce02126f1 |
131103342012145 has 16 divisors (see below), whose sum is σ = 160983121717440. Its totient is φ = 102443278601664.
The previous prime is 131103342012113. The next prime is 131103342012173. The reversal of 131103342012145 is 541210243301131.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 131103342012145 - 25 = 131103342012113 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 155760367 + ... + 156599803.
It is an arithmetic number, because the mean of its divisors is an integer number (10061445107340).
Almost surely, 2131103342012145 is an apocalyptic number.
It is an amenable number.
131103342012145 is a deficient number, since it is larger than the sum of its proper divisors (29879779705295).
131103342012145 is an equidigital number, since it uses as much as digits as its factorization.
131103342012145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1565904.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 131103342012145 its reverse (541210243301131), we get a palindrome (672313585313276).
The spelling of 131103342012145 in words is "one hundred thirty-one trillion, one hundred three billion, three hundred forty-two million, twelve thousand, one hundred forty-five".
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