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131104013351 = 1931222587459
BaseRepresentation
bin111101000011001101…
…0000111110000100111
3110112101212022221020012
41322012122013300213
54122000111411401
6140121154000435
712320610504113
oct1720632076047
9415355287205
10131104013351
1150667885763
12214aa57611b
13c49482c17c
1464b9d70743
153624c3d8bb
hex1e86687c27

131104013351 has 8 divisors (see below), whose sum is σ = 142455974400. Its totient is φ = 120197227320.

The previous prime is 131104013333. The next prime is 131104013393. The reversal of 131104013351 is 153310401131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131104013351 - 222 = 131099819047 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131104013851) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 111293141 + ... + 111294318.

It is an arithmetic number, because the mean of its divisors is an integer number (17806996800).

Almost surely, 2131104013351 is an apocalyptic number.

131104013351 is a deficient number, since it is larger than the sum of its proper divisors (11351961049).

131104013351 is a wasteful number, since it uses less digits than its factorization.

131104013351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 222587509.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 131104013351 its reverse (153310401131), we get a palindrome (284414414482).

The spelling of 131104013351 in words is "one hundred thirty-one billion, one hundred four million, thirteen thousand, three hundred fifty-one".

Divisors: 1 19 31 589 222587459 4229161721 6900211229 131104013351