Base | Representation |
---|---|
bin | 1011111011001000000011… |
… | …0110110101000100101001 |
3 | 1201102100020110102110121112 |
4 | 2332302000312311010221 |
5 | 3204300100410403301 |
6 | 43514500251320105 |
7 | 2522123661446360 |
oct | 276620066650451 |
9 | 51370213373545 |
10 | 13110402044201 |
11 | 41a50aa191640 |
12 | 1578a73150035 |
13 | 7413c85611a7 |
14 | 3347927827d7 |
15 | 17b071be89bb |
hex | bec80db5129 |
13110402044201 has 32 divisors (see below), whose sum is σ = 16637692032000. Its totient is φ = 10033554847680.
The previous prime is 13110402044191. The next prime is 13110402044227. The reversal of 13110402044201 is 10244020401131.
It is not a de Polignac number, because 13110402044201 - 26 = 13110402044137 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13110402044291) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3645350 + ... + 6285648.
It is an arithmetic number, because the mean of its divisors is an integer number (519927876000).
Almost surely, 213110402044201 is an apocalyptic number.
13110402044201 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
13110402044201 is a deficient number, since it is larger than the sum of its proper divisors (3527289987799).
13110402044201 is a wasteful number, since it uses less digits than its factorization.
13110402044201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2641469.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 13110402044201 its reverse (10244020401131), we get a palindrome (23354422445332).
The spelling of 13110402044201 in words is "thirteen trillion, one hundred ten billion, four hundred two million, forty-four thousand, two hundred one".
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