131104033101434 has 4 divisors (see below), whose sum is σ = 196656049652154. Its totient is φ = 65552016550716.

The previous prime is 131104033101331. The next prime is 131104033101467. The reversal of 131104033101434 is 434101330401131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 72886293798409 + 58217739303025 = 8537347^2 + 7630055^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131104033101397 and 131104033101406.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32776008275357 + ... + 32776008275360.

Almost surely, 2^{131104033101434} is an apocalyptic number.

131104033101434 is a deficient number, since it is larger than the sum of its proper divisors (65552016550720).

131104033101434 is an equidigital number, since it uses as much as digits as its factorization.

131104033101434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65552016550719.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 131104033101434 its reverse (434101330401131), we get a palindrome (565205363502565).

The spelling of 131104033101434 in words is "one hundred thirty-one trillion, one hundred four billion, thirty-three million, one hundred one thousand, four hundred thirty-four".