Base | Representation |
---|---|
bin | 1011111011001000000011… |
… | …1110110011100001111011 |
3 | 1201102100020121100200200211 |
4 | 2332302000332303201323 |
5 | 3204300101424310120 |
6 | 43514500404211551 |
7 | 2522124015305164 |
oct | 276620076634173 |
9 | 51370217320624 |
10 | 13110404135035 |
11 | 41a510038a4a9 |
12 | 1578a73999bb7 |
13 | 7413c8b13a7c |
14 | 334792b6876b |
15 | 17b071ead25a |
hex | bec80fb387b |
13110404135035 has 32 divisors (see below), whose sum is σ = 16730826624000. Its totient is φ = 9834191337600.
The previous prime is 13110404135021. The next prime is 13110404135039. The reversal of 13110404135035 is 53053140401131.
It is not a de Polignac number, because 13110404135035 - 227 = 13110269917307 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13110404134988 and 13110404135006.
It is not an unprimeable number, because it can be changed into a prime (13110404135039) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25139866 + ... + 25656064.
It is an arithmetic number, because the mean of its divisors is an integer number (522838332000).
Almost surely, 213110404135035 is an apocalyptic number.
13110404135035 is a deficient number, since it is larger than the sum of its proper divisors (3620422488965).
13110404135035 is a wasteful number, since it uses less digits than its factorization.
13110404135035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 518971.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 13110404135035 its reverse (53053140401131), we get a palindrome (66163544536166).
The spelling of 13110404135035 in words is "thirteen trillion, one hundred ten billion, four hundred four million, one hundred thirty-five thousand, thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •