13110410441 has 4 divisors (see below), whose sum is σ = 13389355392. Its totient is φ = 12831465492.

The previous prime is 13110410437. The next prime is 13110410447. The reversal of 13110410441 is 14401401131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13110410441 - 2² = 13110410437 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13110410447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139472405 + ... + 139472498.

It is an arithmetic number, because the mean of its divisors is an integer number (3347338848).

Almost surely, 2^13110410441 is an apocalyptic number.

It is an amenable number.

13110410441 is a deficient number, since it is larger than the sum of its proper divisors (278944951).

13110410441 is an equidigital number, since it uses as much as digits as its factorization.

13110410441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 278944950.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 13110410441 its reverse (14401401131), we get a palindrome (27511811572).

The spelling of 13110410441 in words is "thirteen billion, one hundred ten million, four hundred ten thousand, four hundred forty-one".