Base | Representation |
---|---|
bin | 1011111011001000001010… |
… | …1101110010111001110001 |
3 | 1201102100022122002220002202 |
4 | 2332302002231302321301 |
5 | 3204300131401333244 |
6 | 43514503323552545 |
7 | 2522124520515362 |
oct | 276620255627161 |
9 | 51370278086082 |
10 | 13110433230449 |
11 | 41a51158522a5 |
12 | 1578a8168b755 |
13 | 741401b600a9 |
14 | 33479697db69 |
15 | 17b07480904e |
hex | bec82b72e71 |
13110433230449 has 4 divisors (see below), whose sum is σ = 13120464167664. Its totient is φ = 13100402293236.
The previous prime is 13110433230397. The next prime is 13110433230467. The reversal of 13110433230449 is 94403233401131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13110433230449 is a prime.
It is a super-2 number, since 2×131104332304492 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13110433230749) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5015466647 + ... + 5015469260.
It is an arithmetic number, because the mean of its divisors is an integer number (3280116041916).
Almost surely, 213110433230449 is an apocalyptic number.
It is an amenable number.
13110433230449 is a deficient number, since it is larger than the sum of its proper divisors (10030937215).
13110433230449 is a wasteful number, since it uses less digits than its factorization.
13110433230449 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10030937214.
The product of its (nonzero) digits is 93312, while the sum is 38.
The spelling of 13110433230449 in words is "thirteen trillion, one hundred ten billion, four hundred thirty-three million, two hundred thirty thousand, four hundred forty-nine".
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