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131104333545034 = 2371771680183041
BaseRepresentation
bin11101110011110100011011…
…001110101011111001001010
3122012012110012102101221201111
4131303310123032223321022
5114141003133341420114
61142500255510240534
736420655414024213
oct3563643316537112
9565173172357644
10131104333545034
11388570434487a3
1212854a9405614a
1358201160c6395
1424536ab00240a
1510254d0707bc4
hex773d1b3abe4a

131104333545034 has 8 divisors (see below), whose sum is σ = 201971540866788. Its totient is φ = 63780486589440.

The previous prime is 131104333545001. The next prime is 131104333545041. The reversal of 131104333545034 is 430545333401131.

It can be written as a sum of positive squares in 2 ways, for example, as 129876724944409 + 1227608600625 = 11396347^2 + 1107975^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1311043335450342 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 885840091447 + ... + 885840091594.

Almost surely, 2131104333545034 is an apocalyptic number.

131104333545034 is a deficient number, since it is larger than the sum of its proper divisors (70867207321754).

131104333545034 is a wasteful number, since it uses less digits than its factorization.

131104333545034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1771680183080.

The product of its (nonzero) digits is 388800, while the sum is 40.

Adding to 131104333545034 its reverse (430545333401131), we get a palindrome (561649666946165).

The spelling of 131104333545034 in words is "one hundred thirty-one trillion, one hundred four billion, three hundred thirty-three million, five hundred forty-five thousand, thirty-four".

Divisors: 1 2 37 74 1771680183041 3543360366082 65552166772517 131104333545034