1311050065361 has 4 divisors (see below), whose sum is σ = 1380052700400. Its totient is φ = 1242047430324.

The previous prime is 1311050065337. The next prime is 1311050065397. The reversal of 1311050065361 is 1635600501131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311050065361 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311050005361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34501317491 + ... + 34501317528.

It is an arithmetic number, because the mean of its divisors is an integer number (345013175100).

Almost surely, 2^{1311050065361} is an apocalyptic number.

It is an amenable number.

1311050065361 is a deficient number, since it is larger than the sum of its proper divisors (69002635039).

1311050065361 is an equidigital number, since it uses as much as digits as its factorization.

1311050065361 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69002635038.

The product of its (nonzero) digits is 8100, while the sum is 32.

Adding to 1311050065361 its reverse (1635600501131), we get a palindrome (2946650566492).

The spelling of 1311050065361 in words is "one trillion, three hundred eleven billion, fifty million, sixty-five thousand, three hundred sixty-one".