Base | Representation |
---|---|
bin | 1011111011001000100111… |
… | …0011101011111010100011 |
3 | 1201102100121220222221111111 |
4 | 2332302021303223322203 |
5 | 3204300402331341303 |
6 | 43514523214124151 |
7 | 2522130464050612 |
oct | 276621163537243 |
9 | 51370556887444 |
10 | 13110552215203 |
11 | 41a5176a30303 |
12 | 1578ab54b0657 |
13 | 7414206bcb81 |
14 | 3347a86b3879 |
15 | 17b07eeadb6d |
hex | bec89cebea3 |
13110552215203 has 4 divisors (see below), whose sum is σ = 13306232099080. Its totient is φ = 12914872331328.
The previous prime is 13110552215179. The next prime is 13110552215207. The reversal of 13110552215203 is 30251225501131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13110552215203 - 25 = 13110552215171 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13110552215207) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97839941838 + ... + 97839941971.
It is an arithmetic number, because the mean of its divisors is an integer number (3326558024770).
Almost surely, 213110552215203 is an apocalyptic number.
13110552215203 is a deficient number, since it is larger than the sum of its proper divisors (195679883877).
13110552215203 is an equidigital number, since it uses as much as digits as its factorization.
13110552215203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 195679883876.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 13110552215203 its reverse (30251225501131), we get a palindrome (43361777716334).
The spelling of 13110552215203 in words is "thirteen trillion, one hundred ten billion, five hundred fifty-two million, two hundred fifteen thousand, two hundred three".
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