Base | Representation |
---|---|
bin | 11000011010111101… |
… | …00000011111110001 |
3 | 1020211201122222010012 |
4 | 30031132200133301 |
5 | 203322404044441 |
6 | 10004554144305 |
7 | 642621454616 |
oct | 141536403761 |
9 | 36751588105 |
10 | 13111003121 |
11 | 5618901777 |
12 | 265aa22095 |
13 | 130c398818 |
14 | 8c53c250d |
15 | 51b07b9eb |
hex | 30d7a07f1 |
13111003121 has 4 divisors (see below), whose sum is σ = 13168761072. Its totient is φ = 13053245172.
The previous prime is 13111003091. The next prime is 13111003133. The reversal of 13111003121 is 12130011131.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13111003121 - 214 = 13110986737 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13111003096 and 13111003105.
It is not an unprimeable number, because it can be changed into a prime (13111003141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28878635 + ... + 28879088.
It is an arithmetic number, because the mean of its divisors is an integer number (3292190268).
Almost surely, 213111003121 is an apocalyptic number.
It is an amenable number.
13111003121 is a deficient number, since it is larger than the sum of its proper divisors (57757951).
13111003121 is an equidigital number, since it uses as much as digits as its factorization.
13111003121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57757950.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 13111003121 its reverse (12130011131), we get a palindrome (25241014252).
The spelling of 13111003121 in words is "thirteen billion, one hundred eleven million, three thousand, one hundred twenty-one".
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