Base | Representation |
---|---|
bin | 10011000101000011101… |
… | …111000001001110101011 |
3 | 11122100011220122020210120 |
4 | 103011003233001032223 |
5 | 132440113431041210 |
6 | 2442151153414323 |
7 | 163503213141546 |
oct | 23050357011653 |
9 | 4570156566716 |
10 | 1311101424555 |
11 | 46604263482a |
12 | 19212526a3a3 |
13 | 96837043b00 |
14 | 47659adb85d |
15 | 2418884b270 |
hex | 13143bc13ab |
1311101424555 has 48 divisors (see below), whose sum is σ = 2276964587520. Its totient is φ = 643924305024.
The previous prime is 1311101424481. The next prime is 1311101424599. The reversal of 1311101424555 is 5554241011131.
It is not a de Polignac number, because 1311101424555 - 210 = 1311101423531 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 444982 + ... + 1679348.
It is an arithmetic number, because the mean of its divisors is an integer number (47436762240).
Almost surely, 21311101424555 is an apocalyptic number.
1311101424555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1311101424555 is a deficient number, since it is larger than the sum of its proper divisors (965863162965).
1311101424555 is a wasteful number, since it uses less digits than its factorization.
1311101424555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1234820 (or 1234807 counting only the distinct ones).
The product of its (nonzero) digits is 12000, while the sum is 33.
Adding to 1311101424555 its reverse (5554241011131), we get a palindrome (6865342435686).
The spelling of 1311101424555 in words is "one trillion, three hundred eleven billion, one hundred one million, four hundred twenty-four thousand, five hundred fifty-five".
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