13111023301 has 4 divisors (see below), whose sum is σ = 13121438400. Its totient is φ = 13100608204.

The previous prime is 13111023287. The next prime is 13111023313. The reversal of 13111023301 is 10332011131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13111023301 - 2¹⁵ = 13110990533 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111020301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5205661 + ... + 5208178.

It is an arithmetic number, because the mean of its divisors is an integer number (3280359600).

Almost surely, 2^13111023301 is an apocalyptic number.

It is an amenable number.

13111023301 is a deficient number, since it is larger than the sum of its proper divisors (10415099).

13111023301 is a wasteful number, since it uses less digits than its factorization.

13111023301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10415098.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13111023301 its reverse (10332011131), we get a palindrome (23443034432).

The spelling of 13111023301 in words is "thirteen billion, one hundred eleven million, twenty-three thousand, three hundred one".