1311104122 has 4 divisors (see below), whose sum is σ = 1966656186. Its totient is φ = 655552060.

The previous prime is 1311104051. The next prime is 1311104149. The reversal of 1311104122 is 2214011131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 2214011131 = 227 ⋅9753353.

It can be written as a sum of positive squares in only one way, i.e., 826620001 + 484484121 = 28751^2 + 22011^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1311104096 and 1311104105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327776029 + ... + 327776032.

Almost surely, 2^1311104122 is an apocalyptic number.

1311104122 is a deficient number, since it is larger than the sum of its proper divisors (655552064).

1311104122 is an equidigital number, since it uses as much as digits as its factorization.

1311104122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 655552063.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 1311104122 is about 36209.1717938977. The cubic root of 1311104122 is about 1094.4915028826.

Adding to 1311104122 its reverse (2214011131), we get a palindrome (3525115253).

The spelling of 1311104122 in words is "one billion, three hundred eleven million, one hundred four thousand, one hundred twenty-two".