1311113100023 has 4 divisors (see below), whose sum is σ = 1311245238648. Its totient is φ = 1310980961400.

The previous prime is 1311113099987. The next prime is 1311113100029. The reversal of 1311113100023 is 3200013111131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311113100023 - 2³⁶ = 1242393623287 is a prime.

It is a super-2 number, since 2×1311113100023² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311113099974 and 1311113100010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311113100029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66054428 + ... + 66074273.

It is an arithmetic number, because the mean of its divisors is an integer number (327811309662).

Almost surely, 2^{1311113100023} is an apocalyptic number.

1311113100023 is a deficient number, since it is larger than the sum of its proper divisors (132138625).

1311113100023 is an equidigital number, since it uses as much as digits as its factorization.

1311113100023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 132138624.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1311113100023 its reverse (3200013111131), we get a palindrome (4511126211154).

The spelling of 1311113100023 in words is "one trillion, three hundred eleven billion, one hundred thirteen million, one hundred thousand, twenty-three".