Base | Representation |
---|---|
bin | 11101110011111010111101… |
… | …101101001000001001001011 |
3 | 122012020010022201101102000002 |
4 | 131303322331231020021023 |
5 | 114141112023211320410 |
6 | 1142503420311433215 |
7 | 36421324405230116 |
oct | 3563727555101113 |
9 | 565203281342002 |
10 | 131111354401355 |
11 | 3885a016547a99 |
12 | 1285631338580b |
13 | 5820994822433 |
14 | 2453b7562b57d |
15 | 1025791c917a5 |
hex | 773ebdb4824b |
131111354401355 has 16 divisors (see below), whose sum is σ = 157587824440800. Its totient is φ = 104719743851520.
The previous prime is 131111354401333. The next prime is 131111354401367. The reversal of 131111354401355 is 553104453111131.
It is not a de Polignac number, because 131111354401355 - 218 = 131111354139211 is a prime.
It is a super-2 number, since 2×1311113544013552 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 396251 + ... + 16198139.
It is an arithmetic number, because the mean of its divisors is an integer number (9849239027550).
Almost surely, 2131111354401355 is an apocalyptic number.
131111354401355 is a deficient number, since it is larger than the sum of its proper divisors (26476470039445).
131111354401355 is a wasteful number, since it uses less digits than its factorization.
131111354401355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15804574.
The product of its (nonzero) digits is 54000, while the sum is 38.
The spelling of 131111354401355 in words is "one hundred thirty-one trillion, one hundred eleven billion, three hundred fifty-four million, four hundred one thousand, three hundred fifty-five".
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