Search a number
-
+
1311115142131 = 4330491049817
BaseRepresentation
bin10011000101000100100…
…011010110001111110011
311122100012212110011202221
4103011010203112033303
5132440130434022011
62442152403421511
7163503440553514
oct23050443261763
94570185404687
101311115142131
1146604a353a73
12192129984897
1396839b37812
144765b86ca0b
1524189b5a971
hex131448d63f3

1311115142131 has 4 divisors (see below), whose sum is σ = 1341606191992. Its totient is φ = 1280624092272.

The previous prime is 1311115142111. The next prime is 1311115142153. The reversal of 1311115142131 is 1312415111131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311115142131 - 29 = 1311115141619 is a prime.

It is a super-2 number, since 2×13111151421312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311115142096 and 1311115142105.

It is not an unprimeable number, because it can be changed into a prime (1311115142111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15245524866 + ... + 15245524951.

It is an arithmetic number, because the mean of its divisors is an integer number (335401547998).

Almost surely, 21311115142131 is an apocalyptic number.

1311115142131 is a deficient number, since it is larger than the sum of its proper divisors (30491049861).

1311115142131 is an equidigital number, since it uses as much as digits as its factorization.

1311115142131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30491049860.

The product of its digits is 360, while the sum is 25.

The spelling of 1311115142131 in words is "one trillion, three hundred eleven billion, one hundred fifteen million, one hundred forty-two thousand, one hundred thirty-one".

Divisors: 1 43 30491049817 1311115142131