13111211311331 has 4 divisors (see below), whose sum is σ = 14984241498672. Its totient is φ = 11238181123992.

The previous prime is 13111211311327. The next prime is 13111211311333. The reversal of 13111211311331 is 13311311211131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13111211311331 - 2² = 13111211311327 is a prime.

It is a super-2 number, since 2×13111211311331² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13111211311297 and 13111211311306.

It is not an unprimeable number, because it can be changed into a prime (13111211311333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 936515093660 + ... + 936515093673.

It is an arithmetic number, because the mean of its divisors is an integer number (3746060374668).

Almost surely, 2^{13111211311331} is an apocalyptic number.

13111211311331 is a deficient number, since it is larger than the sum of its proper divisors (1873030187341).

13111211311331 is an equidigital number, since it uses as much as digits as its factorization.

13111211311331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1873030187340.

The product of its digits is 162, while the sum is 23.

Adding to 13111211311331 its reverse (13311311211131), we get a palindrome (26422522522462).

The spelling of 13111211311331 in words is "thirteen trillion, one hundred eleven billion, two hundred eleven million, three hundred eleven thousand, three hundred thirty-one".